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Post by matthorr on Mar 11, 2015 15:36:51 GMT
This is what I have for my solutions. HW6.pdf (144.31 KB) |
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Deleted
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Post by Deleted on Mar 11, 2015 18:01:52 GMT
Yep, pretty much agree with everything.
We basically did the same thing for #4. Our algebra is a bit different, so our answers look a bit different, but both our A matrices are singular, so I'm not sure if that's a problem.
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Post by matthorr on Mar 11, 2015 18:23:16 GMT
Yeah, that is because \(q_1\) is not in any of the equations. You can still calculate the eigenvalues of A so I don't think that matters. I think when Chopra was talking about the matrix not being invertible, he was talking about the matrix on the LHS in front of \(\dot{x}\).
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