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Post by Br. Marius on Apr 10, 2015 17:44:23 GMT
In a circulation control rotor, the aerodynamic moment about mid-chord is function of geometric angle \(\alpha\), blowing momentum coefficient \(C_\mu\), and Mach number M. The blowing momentum coefficient is defined as the following:
\(C_\mu=\frac{(\dot m)V_j}{0.5(\rho)V^2c}\) where Vj is jet velocity and is the mass rate of jet. The blade operates at a fixed collective pitch and the lift vector is controlled by adjusting blowing level. Calculate perturbation moment in terms of airflow components Up and UT and pitch θ (steady and perturbation values). Also include noncirculatory forces.
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Post by matthorr on Apr 13, 2015 15:15:06 GMT
Given: \begin{align*} C_{M_\beta} &= C_{M_\beta}\left(\alpha, C_\mu, M\right) \\ C_\mu &= \frac{\dot{m}V_j}{\frac{1}{2}\rho V^2 c} \end{align*} The moment is given by \begin{equation} M = \frac{1}{2}\rho V^2c^2C_{m_\beta}-Lx_a \end{equation} where \(x_a\) is the distance between the aerodynamic center (location of lift) and the elastic axis. Using trim values for the coefficients, \begin{equation} M_{trim} = \frac{1}{2}\rho V^2c^2C_{M_\beta}-\frac{1}{2}\rho V^2 c C_l x_a \end{equation} where \(C_l = C_l(\alpha,C_\mu)\). Also, \begin{align} V &= \sqrt{U_T^2+U_P^2} \\ \alpha &= \theta - \tan^{-1}\frac{U_P}{U_T} \approx \theta - \frac{U_P}{U_T} \\ M &= M_{tip}\frac{V}{\Omega R} \end{align} The circulatory perturbation equations are \begin{align} \label{eq:deltaM} \delta M_C &= \rho V\delta V c^2C_{M_\beta} + \frac{1}{2}\rho V^2c^2\delta C_{M_\beta} - \rho V \delta V c C_l x_a - \frac{1}{2}\rho V^2 c \delta C_l x_a \\ \label{eq:deltaV} \delta V &= \frac{U_P\delta U_P + U_T\delta U_T}{V} \\ \delta C_{M_\beta} &= C_{M_{\beta_\alpha}} \delta \alpha + C_{M_{\beta_\mu}} \delta C_\mu + C_{M_{\beta_M}} \delta M \\ \delta \alpha &= \delta\theta - \frac{U_T\delta U_P - U_P\delta U_T}{U_T^2} \\ \delta C_\mu &= \frac{-2C_\mu \delta V}{V} \\ \delta M &= \frac{M_{tip}}{\Omega R}\delta V \\ \label{eq:deltaCl} \delta C_l &= C_{l_\alpha}\delta \alpha + C_{l_\mu}\delta C_\mu \end{align} The non-circulatory moment is \begin{equation} M_{NC} = \frac{1}{4}\pi\rho\Omega^2c^3\left[r\left(\frac{1}{4}+\frac{x_a}{c}\right)\ddot{\beta}-r\left(\frac{1}{2}+\frac{x_a}{c}\right)\dot{\theta}-c\left(\frac{3}{32}+\frac{1}{2}\frac{x_a}{c}\right)\ddot{\theta}\right] \end{equation} Substituting equations \eqref{eq:deltaV} through \eqref{eq:deltaCl} into \eqref{eq:deltaM} \begin{align} \delta M_C &= \rho c^2C_{M_\beta} \left(U_P\delta U_P + U_T\delta U_T\right) \\ &+ \frac{1}{2}\rho \left(U_T^2+U_P^2\right)c^2C_{M_{\beta_\alpha}}\left(\delta \theta - \frac{U_T\delta U_P - U_P\delta U_T}{U_T^2}\right) \nonumber \\ &-\rho c^2C_{M_{\beta_\mu}}C_\mu \left(U_P\delta U_P + U_T\delta U_T\right) \nonumber \\ &+\frac{1}{2}\rho c^2C_{M_{\beta_M}} \sqrt{U_T^2+U_P^2}\left(\frac{M_{tip}}{\Omega R}\right)\left(U_P\delta U_P + U_T\delta U_T\right) \nonumber \\ &-\rho cC_lx_a\left(U_P\delta U_P + U_T\delta U_T\right) \nonumber \\ &-\frac{1}{2}\rho c x_a\left(U_T^2+U_P^2\right)C_{l_\alpha}\left(\delta\theta - \frac{U_T\delta U_P - U_P\delta U_T}{U_T^2}\right) \nonumber \nonumber \\ &+\rho c x_a C_{l_\mu}C_\mu\left(U_P\delta U_P + U_T\delta U_T\right) \nonumber \end{align} The terms could be rearranged to group each perturbation (i.e. \(\delta M = \delta U_P(\ldots) + \delta U_T(\ldots) + \delta \theta(\ldots)\)).
The final result is \begin{equation} \delta M = \delta M_C + M_{NC} \end{equation}
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Post by Br. Marius on Apr 13, 2015 15:28:30 GMT
The process looks good. Very good.
It elicits a question from me, though. I was looking at the \(M_{NC}\) expression (as it is given in the text, which is identical to what you have here) and the units don't line up. Inside of the square brackets, there is a length/time^2 term, then a length/time term, then a length/time^2 term. I've been trying to figure out how you arrive at that expression to try and figure out what I'm missing, but nothing yet.
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Post by matthorr on Apr 13, 2015 15:59:37 GMT
It's magic... inside of each parenthesis is non-dimensional. The derivatives don't make sense to me - it looks like there should be an \(\Omega\) in the middle term to make everything work out...
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